312-50v13 Quiz Torrent: Certified Ethical Hacker Exam (CEHv13) - 312-50v13 Quiz Braindumps & 312-50v13 Study Guide

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ECCouncil Certified Ethical Hacker Exam (CEHv13) Sample Questions (Q535-Q540):

NEW QUESTION # 535
When considering how an attacker may exploit a web server, what is web server footprinting?

A. When an attacker uses a brute-force attack to crack a web-server password
B. When an attacker gathers system-level data, including account details and server names
C. When an attacker implements a vulnerability scanner to identify weaknesses
D. When an attacker creates a complete profile of the site's external links and file structures

Answer: B

NEW QUESTION # 536
Mirai malware targets loT devices. After infiltration, it uses them to propagate and create botnets that then used to launch which types of attack?

A. Birthday attack
B. MITM attack
C. Password attack
D. DDoS attack

Answer: D

NEW QUESTION # 537
You are an ethical hacker contracted to conduct a security audit for a company. During the audit, you discover that the company's wireless network is using WEP encryption. You understand the vulnerabilities associated with WEP and plan to recommend a more secure encryption method. Which of the following would you recommend as a Suitable replacement to enhance the security of the company's wireless network?

A. WPA2-PSK with AES encryption
B. Open System authentication
C. MAC address filtering
D. SSID broadcast disabling

Answer: A

Explanation:
WEP encryption is an outdated and insecure method of protecting wireless networks from unauthorized access and eavesdropping. WEP uses a static key that can be easily cracked by various tools and techniques, such as capturing the initialization vectors, brute-forcing the key, or exploiting the weak key scheduling algorithm1. Therefore, you should recommend a more secure encryption method to enhance the security of the company's wireless network.
One of the most suitable replacements for WEP encryption is WPA2-PSK with AES encryption. WPA2 stands for Wi-Fi Protected Access 2, which is a security standard that improves upon the previous WPA standard. WPA2 uses a robust encryption algorithm called AES, which stands for Advanced Encryption Standard. AES is a block cipher that uses a 128-bit key and is considered to be very secure and resistant to attacks2.
WPA2-PSK stands for WPA2 Pre-Shared Key, which is a mode of WPA2 that uses a passphrase or a password to generate the encryption key. The passphrase or password must be entered by the users who want to connect to the wireless network. The key is then derived from the passphrase or password using a function called PBKDF2, which stands for Password-Based Key Derivation Function 2. PBKDF2 adds a salt and a number of iterations to the passphrase or password to make it harder to crack3.
WPA2-PSK with AES encryption offers several advantages over WEP encryption, such as:
* It uses a dynamic key that changes with each session, instead of a static key that remains the same.
* It uses a stronger encryption algorithm that is more difficult to break, instead of a weaker encryption algorithm that is more vulnerable to attacks.
* It uses a longer key that provides more security, instead of a shorter key that provides less security.
* It uses a more secure key derivation function that adds complexity and randomness, instead of a simple key generation function that is predictable and flawed.
Therefore, you should recommend WPA2-PSK with AES encryption as a suitable replacement to enhance the security of the company's wireless network.
References:
* Wireless Security - Encryption - Online Tutorials Library
* WiFi Security: WEP, WPA, WPA2, WPA3 And Their Differences - NetSpot
* WPA2-PSK (Wi-Fi Protected Access 2 Pre-Shared Key)

NEW QUESTION # 538
You are an ethical hacker tasked with conducting an enumeration of a company's network. Given a Windows system with NetBIOS enabled, port 139 open, and file and printer sharing active, you are about to run some nbtstat commands to enumerate NetBIOS names. The company uses |Pv6 for its network. Which of the following actions should you take next?

A. Switch to an enumeration tool that supports IPv6
B. Utilize Nmap Scripting Engine (NSE) for NetBIOS enumeration
C. Use nbtstat -c to get the contents of the NetBIOS name cache
D. use nbtstat -a followed by the IPv6 address of the target machine

Answer: A

Explanation:
The nbtstat command is a Windows utility that displays NetBIOS over TCP/IP (NetBT) protocol statistics, NetBIOS name tables, and the NetBIOS name cache. However, the nbtstat command does not support IPv6 addresses, which are the standard format for the Internet Protocol version 6 (IPv6). Therefore, using the nbtstat command with IPv6 addresses will result in an error message or no output. To enumerate NetBIOS names on a network that uses IPv6, you should switch to an enumeration tool that supports IPv6, such as Nmap, which is a network scanning and security auditing tool. Nmap has a scripting engine (NSE) that allows users to write and execute scripts for various network tasks, including NetBIOS enumeration. Nmap can also detect the operating system, services, and vulnerabilities of the target machines, regardless of the IP version they use. References:
* Nbtstat Command - Computer Hope
* Nbtstat CMD: Windows Network Command Line Prompt
* [Nmap Scripting Engine (NSE) Documentation]

NEW QUESTION # 539
The change of a hard drive failure is once every three years. The cost to buy a new hard drive is $300. It will require 10 hours to restore the OS and software to the new hard disk. It will require a further 4 hours to restore the database from the last backup to the new hard disk. The recovery person earns $10/hour. Calculate the SLE, ARO, and ALE. Assume the EF = 1(100%). What is the closest approximate cost of this replacement and recovery operation per year?

A. $440
B. $146
C. $100
D. $1320

Answer: B

Explanation:
1. AV (Asset value) = $300 + (14 * $10) = $440 - the cost of a hard drive plus the work of a recovery person, i.e.how much would it take to replace 1 asset? 10 hours for resorting the OS and soft + 4 hours for DB restore multiplies by hourly rate of the recovery person.
2. SLE (Single Loss Expectancy) = AV * EF (Exposure Factor) = $440 * 1 = $440
3. ARO (Annual rate of occurrence) = 1/3 (every three years, meaning the probability of occurring during 1 years is 1/3)
4. ALE (Annual Loss Expectancy) = SLE * ARO = 0.33 * $440 = $145.2

NEW QUESTION # 540
......

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312-50v13 Quiz Torrent: Certified Ethical Hacker Exam (CEHv13) - 312-50v13 Quiz Braindumps & 312-50v13 Study Guide

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ECCouncil Certified Ethical Hacker Exam (CEHv13) Sample Questions (Q535-Q540):

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